延长$DG$交$AF$的延长线于点$H$,作$GM\bot BH$于点$M$,
$\because i=1:0.75=\frac{GM}{FM}$,
$\therefore \frac{GM}{FM}=\frac{4}{3}$,
$\because FG=5$米,
$\therefore GM=4$米,$FM=3$米,
$\because CF=1$米,
$\therefore CM=4$米,
$\because AE=CH=6$米,
$\therefore MH=2$米,
$\because GM\bot AF$,$DC\bot AF$,
$\therefore GM$∥$DC$,
$\therefore \frac{MH}{CH}=\frac{MG}{DC}$,即$\frac{2}{6}=\frac{4}{CD}$,
$\therefore CD=12$米,
$\therefore AB=CD=12$米,
答:电线杆$AB$的高度为$12$米.
标签:电线杆,AB,FG
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